Question

A ball was kicked upward with a velocity of 64.2 m/s on the moon, where the acceleration due to gravity is only 1.67 m/s. How fast was it going after 1.5 seconds?

Answer 1

The ball kicked upward on the moon with an initial velocity of 64.2 m/s would have a velocity of 61.695 m/s after 1.5 seconds, taking into account that the moon's gravity is 1.67 m/s².

Step-by-step explanation:

The question asks for the velocity of a ball was kicked upward on the moon after a certain time has passed. Given that the initial velocity of 64.2 m/s on the moon and the acceleration due to gravity is only 1.67 m/s, we can use the kinematic equation to find the velocity after 1.5 seconds.

Using the equation:
V = V0 - g*t
where V is the final velocity, V0 is the initial velocity, g is the acceleration due to gravity, and t is the time elapsed, we can plug in the values:

V = 64.2 m/s - (1.67 m/s2 * 1.5 s) = 64.2 m/s - 2.505 m/s = 61.695 m/s.

So after 1.5 seconds, the ball's velocity would be 61.695 m/s (assuming no other forces act on the ball, such as atmospheric drag, which is absent on the moon).