Final Answer:
It will take approximately 14.2 seconds to reach a speed of 80 m/s.
Step-by-step explanation:
To determine the time required to reach a speed of 80 m/s, we can use the kinematic equation:
![\[v_f = v_i + a \cdot t.\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/tcnxzle1yr9a4zvrcp3cgfjr96yuznuyx2.png)
Where:
is the final velocity (80 m/s),
is the initial velocity (0 m/s, as the speed is initially not given),
is the acceleration (4.5 m/s²), and
is the time.
Rearranging the equation to solve for time
, we get:
![\[t = (v_f - v_i)/(a).\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/wfk4kghfpsti2qkue46sm3vbkfy90k6vsz.png)
Since the initial velocity
is not provided, we assume it to be 0 m/s.
![\[t = \frac{80 \, \text{m/s} - 0 \, \text{m/s}}{4.5 \, \text{m/s²}}.\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/pnr0gvxcexki2w4q490xve6nzbczxvuyip.png)
Solving the expression gives us the time
it takes to reach a speed of 80 m/s. Substituting the values:
![\[t \approx (80)/(4.5) \approx 17.78 \, \text{seconds}.\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/9qi66fhuumsxuy8c0qkmotc6r57ficwdji.png)
However, the question mentions passing through a 75-meter tunnel in 2.8 seconds, so we subtract this time:
![\[t_{\text{adjusted}} = 17.78 - 2.8 \approx 14.2 \, \text{seconds}.\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/v6i34p3cm0gu4cwwy8i5mexyy9jumadg86.png)
Therefore, it will take approximately 14.2 seconds to reach a speed of 80 m/s.