Final answer:
The mass of 1.34 x 10^25 atoms of tin is approximately 2640.075 grams, calculated by first determining the number of moles of tin and then multiplying by the molar mass of tin, which is 118.7 g/mol.
Step-by-step explanation:
To calculate the mass of 1.34 x 1025 atoms of tin (Sn), we need to use Avogadro's number and the molar mass of tin. First, we should confirm the atomic and mass numbers for an isotope of tin. From Exercises 2.2.1, 3.2.1, and 3.5.1, we know that the number of protons in a tin atom is 50, and the number of neutrons is 68, giving us an atomic number of 50 and a mass number of 118.
Next, we will use the molar mass of tin provided in the figures which is 118.7 g for 1 mole (6.022 x 1023 atoms) of tin. To find the mass of 1.34 x 1025 atoms, we use the ratio:
- Calculate moles of tin using Avogadro's number: (1.34 x 1025 atoms) / (6.022 x 1023 atoms/mol) = 22.25 mol.
- Calculate the mass using the molar mass: (22.25 mol) x (118.7 g/mol) = 2640.075 grams of tin.
Therefore, the mass of 1.34 x 1025 atoms of tin is approximately 2640.075 grams.