Question

While being chased by a dinosaur, Dr. Malcolm takes a running jump, leaping horizontally off of a 6.1 meter high cliff, over a river and lands 6.7 meters away from the edge of the cliff. How fast was he running?

Answer 1

Dr. Malcolm was running at a speed of 3.35 m/s.

Step-by-step explanation:

To find the speed at which Dr. Malcolm was running, we can use the equation for horizontal projectile motion. The fact that he lands 6.7 meters away from the edge of the cliff tells us the horizontal distance traveled. Since there is no horizontal acceleration, we can use the equation:

Distance = Velocity * Time

where Distance is the horizontal distance traveled, Velocity is the speed at which Dr. Malcolm was running, and Time is the time it took for him to travel that distance. Rearranging the equation, we have:

Velocity = Distance / Time

Substituting the given values, we get:

Velocity = 6.7 m / 2 s = 3.35 m/s