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Solve for x in the equation x^(2)-4x-9=29 x=2+-\sqrt(42) x=2+-\sqrt(33) x=2+-\sqrt(34) x=4+-\sqrt(42)

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Final answer:

To solve the quadratic equation x^2 - 4x - 9 = 29, it is first simplified to x^2 - 4x - 38 = 0. Using the quadratic formula, we find the solutions x = 4 + √(42) and x = 4 - √(42).

Step-by-step explanation:

To solve the quadratic equation x^2 - 4x - 9 = 29, we first need to bring the equation to the standard quadratic form ax^2 + bx + c = 0. By subtracting 29 from both sides, we get x^2 - 4x - 38 = 0.

Next, we use the quadratic formula x = -b ± √(b^2 - 4ac) / 2a to find the values of x. Substituting the coefficients from our equation (a = 1, b = -4, c = -38) into the formula gives us:

x = -(-4) ± √((-4)^2 - 4*1*(-38)) / (2*1)
x = 4 ± √(16 + 152) / 2
x = 4 ± √(168) / 2
x = 4 ± √(4*42) / 2
x = 4 ± 2√(42) / 2
x = 4 ± √(42)

The solutions are x = 4 + √(42) and x = 4 - √(42).

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