Question

In 1934, the wind speed on Mt. Washington in New Hampshire reached a record high. Suppose a very sturdy glider is launched in this wind, so that in 45.0 seconds the glider reaches the speed of the wind. If the glider undergoes a constant acceleration of 2.29 m/s², what is the wind's speed? Assume the glider started from rest.

Answer 1

The wind's speed on Mt. Washington that the glider reached, starting from rest and undergoing constant acceleration, is calculated to be 103.05 m/s.

Step-by-step explanation:

To calculate the wind's speed, we can use the kinematic equation for constant acceleration that relates the final velocity (v), initial velocity (u), acceleration (a), and time (t):

v = u + at

Given that the glider starts from rest, the initial velocity (u) is 0 m/s. The acceleration (a) is given as 2.29 m/s², and the time (t) taken to reach the wind's speed is 45.0 seconds.

Substituting these values into the equation:

v = 0 m/s + (2.29 m/s²)(45.0 s)

v = 103.05 m/s

Therefore, the wind's speed on Mt. Washington that the glider matched is 103.05 m/s.