Question

A golf ball is hit with an initial velocity of 40 fps. The equation is h = -8t^2 + 40t. How high is the ball after 2 seconds?

Answer 1

The height of the golf ball after 2 seconds is 48 feet.

Step-by-step explanation:

The height of the golf ball after 2 seconds can be calculated using the equation h = -8t^2 + 40t, where h represents the height in feet and t represents the time in seconds. Plugging in t = 2 into the equation, we get:

h = -8(2)^2 + 40(2)

h = -8(4) + 80

h = -32 + 80

h = 48 feet

Therefore, the golf ball is 48 feet high after 2 seconds.