Question

Which equation has a solution of all real numbers?

a. 5k - (6k - 18) = 9 - k + 17
b. 14 - 5(y + 10) = 4 - 8(y + 5)
c. 6(-2w - 3) = -4(3w + 7) + 10
d. 7m - 2(2m + 3) = 8 - (3m - 10)

Answer 1

Option c) 6(-2w - 3) = -4(3w + 7) + 10 has a solution of all real numbers.

Step-by-step explanation:

The equation that has a solution of all real numbers is option c) 6(-2w - 3) = -4(3w + 7) + 10.

To solve this equation, simplify both sides and combine the like terms:

6(-2w) - 6(3) = -4(3w) - 4(7) + 10

-12w - 18 = -12w - 28 + 10

-12w - 18 = -12w - 18

As you can see, the equation is satisfied for every value of w, which means that it has a solution of all real numbers.