Final answer:
The mass of ice that could be made when 91,000 J of energy is removed from water at 0.0°C is 0.272 kg or 272 grams, calculated using the latent heat of fusion of water.
Step-by-step explanation:
To determine the mass of ice that can be formed from water at 0.0°C when 91,000 J of energy is removed, we need to use the concept of latent heat of fusion. The latent heat of fusion of water (Lf) is the amount of heat energy required to convert 1 kilogram of ice into water at the melting point without changing its temperature, which is approximately 334 kJ/kg (334,000 J/kg).
To calculate the mass (‘m’), we can rearrange the formula:
Q = m × Lf
where Q is the heat energy removed in joules, m is the mass in kilograms, and Lf is the latent heat of fusion. Plugging in the values we get:
m = Q / Lf
m = 91,000 J / 334,000 J/kg
m = 0.272 kg
Therefore, 0.272 kg (272 grams) of ice could be formed when 91,000 J of energy is removed from water at 0.0°C.