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If x2 - 6x - 16, what are the x-intercepts?​
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17 votes
If x2 - 6x - 16, what are the x-intercepts?​

User Oren Bochman
by
6.9k points

2 Answers

10 votes

Answer:

(-2, 0) and (8, 0)

Explanation:

x2 - 6x - 16 = 0

(x - 8)(x + 2) = 0

x = -2, 8.

User Arun C
by
7.4k points
10 votes
If that’s meant to be x^2 - 6x - 16
Then factorise to (x+2)(x-8)
So x intercepts are -2 and 8
User DocOc
by
7.2k points
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