Question

Solve the simultaneous equation:
4x - 3y = 17,
3x^2 - 3y^2 + x - 4y = 73

Answer 1

To solve the simultaneous equations 4x - 3y = 17 and 3x^2 - 3y^2 + x - 4y = 73, start by expressing y in terms of x from the first equation, substituting it in the second equation, solving the resulting quadratic for x, and then using this to find y.

Step-by-step explanation:

To solve the simultaneous equation: 4x - 3y = 17 and 3x^2 - 3y^2 + x - 4y = 73, we will proceed with the following steps:

1. First, from the first equation (4x - 3y = 17), we solve for one variable in terms of the other. Let's solve for y:
   y = (4x - 17) / 3.
2. Next, we substitute this expression for y in the second equation (3x^2 - 3y^2 + x - 4y = 73). After substitution, we get a quadratic equation in terms of x that we need to solve.
3. Once we find the value of x, we can substitute it back in the expression for y to find the value of y.
4. This can involve complex algebraic steps and may yield one or more solutions for the simultaneous equations.