Final answer:
The pressure at the bottom of the wall due to the 6-meter-high water column is 58860 Pascal (58.86 kPa), calculated using the formula P = ρgh, where ρ is the density of water, g is the acceleration due to gravity, and h is the height of the water.
Step-by-step explanation:
To calculate the pressure exerted by water at the bottom of a wall, given that the water height is 6 meters, we use the formula for pressure due to a liquid column, which is P = ρgh. Here, ρ (rho) is the density of water, which is 1000 kg/m³ for freshwater, g is the acceleration due to gravity, which is approximately 9.81 m/s², and h is the height of the water column, which is 6 m in this case.
Plugging in the values, we get:
P = 1000 kg/m³ * 9.81 m/s² * 6 m
P = 58860 N/m² or Pascal (Pa)
Thus, the pressure at the bottom of the wall due to the 6m high water column is 58860 Pa or 58.86 kPa.