Final answer:
The displacement of an object thrown straight up after 2.0 seconds with an initial velocity of 15 m/s is 10.4 m. The calculation involves a kinematic equation accounting for initial velocity and acceleration due to gravity. The correct numeric solution with units is 10.4 meters.
Step-by-step explanation:
The question involves calculating the displacement of an object thrown straight up after 2.0 seconds with an initial velocity of 15 m/s. To solve this, we can use the kinematic equation for displacement in free fall: s = ut + (1/2)at^2, where s is displacement, u is initial velocity, t is time, and a is acceleration due to gravity (which is approximately 9.8 m/s^2 downward).
Given that u = 15 m/s, t = 2.0 s, and a = -9.8 m/s^2 (negative sign indicates acceleration is in the opposite direction of the initial velocity), we can plug these values in to get: s = (15 m/s)(2.0 s) + (1/2)(-9.8 m/s^2)(2.0 s)^2.
Doing the calculation:
s = 30 - 19.6
s = 10.4 meters
The correct answer is A. 10.4 m, which represents the numeric solution with the correct unit for the displacement of the object at 2.0 seconds.