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Given the function f(x) = ax^3 +bx-1, and f(2)=3, and f(1) =7/4
Find the value of (-4a).

1 Answer

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Final answer:

To determine the value of -4a, we solve a system of equations created by substituting x = 2 and x = 1 into the function f(x) = ax^3 + bx - 1. Through the solving process, we find that a = -1/4, hence -4a = 1.

Step-by-step explanation:

To find the value of -4a given the function f(x) = ax^3 + bx - 1, and knowing that f(2) = 3 and f(1) = 7/4, we need to substitute these x values into the given function and solve the system of equations they create.

First, substituting x = 2:

  • 3 = a(2)^3 + b(2) - 1
  • 3 = 8a + 2b - 1
  • 4 = 8a + 2b

Second, substituting x = 1:

  • 7/4 = a(1)^3 + b(1) - 1
  • 7/4 = a + b - 1
  • 11/4 = a + b

From these equations, we can solve for a and b.

4 = 8a + 2b (1)

11/4 = a + b (2)

Multiplying equation (2) by 2 gives:

11/2 = 2a + 2b

Subtracting this from equation (1) we get:

4 - 11/2 = 8a + 2b - (2a + 2b)

8/2 - 11/2 = 6a

-3/2 = 6a

a = -1/4

Finally, we find that -4a = -4(-1/4) = 1.

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