Final answer:
The speed of the baseball after 5 seconds when thrown straight up with an initial velocity of 49 m/s is 0 m/s.
Step-by-step explanation:
To find the speed of the baseball after 5 seconds when thrown straight up with an initial velocity of 49 m/s, we can use the equation for vertical motion:
v = u + gt
where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
Solving for v, we get:
v = u - gt
Substituting the given values:
v = 49 - 9.8(5)
v = 49 - 49
v = 0 m/s
Therefore, the speed of the baseball after 5 seconds is 0 m/s.