Question

A farmer collects data on how many days it takes an orange to grow from a bud to a full, ripe fruit. The data is normally distributed with a mean of 17 days and a standard deviation of 1.1 days. What would be the z-score for an orange that takes 19 days to fully grow?

Answer 1

The z-score for an orange that takes 19 days to fully grow is 1.82.

Step-by-step explanation:

To find the z-score for an orange that takes 19 days to fully grow, we can use the formula for z-score:

z = (x - μ) / σ

where x is the value we want to standardize (in this case, 19), μ is the mean (17), and σ is the standard deviation (1.1).

Applying the formula, we get:

z = (19 - 17) / 1.1 = 1.82

Therefore, the z-score for an orange that takes 19 days to fully grow is 1.82.