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a straight line RS passes through (0,-4) and has a gradient of ½.Find the x-intercept of the straight line.​

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Final answer:

To determine the x-intercept of the straight line with a gradient of ½, the equation y = ½x - 4 is used. Setting y to 0 and solving for x gives an x-intercept of (8, 0).

Step-by-step explanation:

The student asks for the x-intercept of a straight line with a gradient of ½ that passes through the point (0,-4). To find the x-intercept, we can use the equation of the line in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

The slope (gradient) is ½ and the line passes through (0, -4), so the y-intercept is -4. Therefore, the equation of the line is y = ½x - 4.

To find the x-intercept, we set y to 0 and solve for x:
0 = ½x - 4
½x = 4
x = 8

Therefore, the x-intercept of the straight line RS is at the point (8, 0).

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