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An object goes from a speed of 9 m/s to a total stop (Om/s) in 3 s. What

is the object's acceleration?

User MasterXD
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1 Answer

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Final answer:

To calculate the object's acceleration from 9 m/s to 0 m/s over 3 s, use the formula a = Δv/Δt, resulting in an acceleration of -3 m/s², indicating deceleration.

Step-by-step explanation:

The object’s acceleration can be calculated using the formula a = Δv / Δt, where Δv is the change in speed and Δt is the change in time. In this case, the object goes from a speed of 9 m/s to 0 m/s in 3 s. Plugging in the values, the acceleration is a = (0 m/s - 9 m/s) / 3 s = -3 m/s². The negative sign indicates that the object is decelerating. In this context, the object experiences a negative acceleration due to the opposing directions of initial and final velocities. The negative sign elucidates that the object is moving in a positive direction, illustrating a slowing or decelerating motion. This understanding is crucial for analyzing and interpreting the dynamics of the object's motion, providing insights into its behavior during the given time interval.

User Letstango
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