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A rocket-driven sled running on a straight, level track has been used to study the physio-logical effects of large accelerations on astronauts. One such sled can attain a speed of367 m/s in 1.6 s starting from rest.What is the acceleration of the sled, assuming it is constant? How far does the sled travel in 1.6s starting from rest?

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Final answer:

The acceleration of the sled is 229.375 m/s², and it travels 293.6 meters in 1.6 seconds starting from rest.

Step-by-step explanation:

To calculate the acceleration of the sled, we use the formula a = Δv / t, where Δv is the change in velocity and t is the time. Given that the sled reaches a velocity of 367 m/s in 1.6 seconds from rest, the acceleration a is calculated as:

a = (367 m/s) / (1.6 s) = 229.375 m/s².

To find out how far the sled travels in 1.6 seconds starting from rest, we can use the kinematic equation d = (v_i × t) + (1/2 × a × t²), where v_i is the initial velocity, and a is the acceleration. Since the sled starts from rest, v_i = 0, and the displacement d can be calculated as:

d = (0 × 1.6 s) + (1/2 × 229.375 m/s² × (1.6 s)²) = 0 m + (1/2 × 229.375 m/s² × 2.56 s²) = 293.6 m.

This means the sled travels a distance of 293.6 meters in 1.6 seconds.

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