Question

Find the tenth term of the geometric sequence with a1 = 3, and r = 2.

1377
1526
1659
1536
1500

Answer 1

General term of GP: a

1

r

n−1

10

th

term of GP =a

1

r

9

=45(0.2)

9

=23040×10

−9

=2.304×10

−5

Answer 2

1536

Explanation:

The n th term of a geometric sequence is

`a_(n)` = a₁
`r^(n-1)`

Here a₁ = 3 and r = 2 , then

a₁₀ = 3 ×
`2^(9)` = 3 × 512 = 1536