The perimeter of triangle ABC with vertices A(1,1), B(7,1), and C(1,9) is calculated using the distance formula for each pair of vertices, resulting in a total perimeter of 24 units.
To find the perimeter of a triangle with given vertices, we can calculate the distances between each pair of points (A to B, A to C, and B to C) using the distance formula:
- Distance AB = √((x2 - x1)² + (y2 - y1)²)
- Distance AC = √((x2 - x1)² + (y2 - y1)²)
- Distance BC = √((x2 - x1)² + (y2 - y1)²)
For vertices A(1,1), B(7,1), and C(1,9), the distances are calculated as:
- Distance AB = √((7 - 1)² + (1 - 1)²) = 6
- Distance AC = √((1 - 1)² + (9 - 1)²) = 8
- Distance BC = √((7 - 1)² + (9 - 1)²) = √(36 + 64) = √100 = 10
Sum these distances to find the perimeter:
Perimeter of Triangle ABC = AB + AC + BC = 6 + 8 + 10 = 24
The above question is incomplete, the complete question is:
Find the perimeter of triangle ABC with vertices A(1,1) B(,7,1) C(1,9)?