Question

A particle moves in a straight line with a constant acceleration. Its initial velocity and its final velocity after 8s is 10 ms .Find the acceleration and the displacement ofthe particle after 16s.

Answer 1

The acceleration is 1.25 m/s² and the displacement after 16 seconds is 260 meters.

Step-by-step explanation:

The acceleration can be found using the formula:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Given that the initial velocity (u) is 10 m/s and the final velocity (v) is 10 m/s, we can rearrange the formula to solve for acceleration (a):
a = (v - u) / t
Plugging in the values, we get:
a = (10 - 0) / 8 = 1.25 m/s²

To find the displacement after 16 seconds, we can use the formula:
s = ut + (1/2)at²
where s is the displacement, u is the initial velocity, a is the acceleration, and t is the time.

Using the values u = 10 m/s, a = 1.25 m/s², and t = 16 s, plugging them into the formula, we get:
s = 10 * 16 + (1/2) * 1.25 * (16)² = 160 + 100 = 260 meters.