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You are in your car driving at 20m/s. You need to pass a slow moving truck on the freeway. You accelerate at a constant rate of 0.13 m/s² for 4 seconds as you pass the truck. What distance do you cover during this time?

User Oaklodge
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1 Answer

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Final answer:

The car accelerates at a constant rate for 4 seconds, covering a distance of 81.04 meters during this time.

Step-by-step explanation:

To calculate the distance covered by a car accelerating at a constant rate, we can use the kinematic equation:

s = ut + ½at²

where:

  • s is the distance covered in meters (m)
  • u is the initial velocity in meters per second (m/s)
  • a is the acceleration in meters per second squared (m/s²)
  • t is the time in seconds (s)

Given the initial velocity u = 20 m/s, acceleration a = 0.13 m/s², and time t = 4 s, we can plug these values into the equation:

s = (20 m/s)(4 s) + ½(0.13 m/s²)(4 s)²

s = 80 m + 0.5 * 0.13 m/s² * 16 s²

s = 80 m + 1.04 m

s = 81.04 m

The car covers a distance of 81.04 meters while passing the truck.

User Yong
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