Question

A light bulb operating on 110 volts has 0.50 ampere of current passing through it. How much energy does the bulb convert to heat and light in 5 minutes?

What is its power rating in watts (W)?

Answer 1

The light bulb with a voltage of 110 volts and a current of 0.50 amperes has a power rating of 55 watts and converts 16493.4 joules of energy into heat and light over 5 minutes.

Step-by-step explanation:

The question involves calculating the energy conversion and power rating of a light bulb that operates on 110 volts with 0.50 ampere of current passing through it over a period of 5 minutes.

First, the power of the bulb in watts (W) can be calculated using the formula P = V × I, where P is power, V is voltage, and I is current. In this case,

P = 110 volts × 0.50 amperes = 55 watts (W)

This tells us the power rating of the bulb.

Next, to find the energy converted to heat and light, we use the formula E = P × t, where E is energy in watt-hours (Wh), P is power in watts, and t is time in hours. Since 5 minutes is 1/12 of an hour (or 0.0833 hours), the calculation is as follows:

E = 55 watts × 0.0833 hours = 4.5815 watt-hours (Wh)

To convert watt-hours to joules (since 1 Wh = 3600 joules), we get:

E = 4.5815 Wh × 3600 joules/Wh = 16493.4 joules

The bulb converts 16493.4 joules of electrical energy into heat and light in 5 minutes, and it has a power rating of 55 watts.