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What is an equation of a line that passes through the point (0,3) and is perpendicular to the line whose equation is y = 21 - 1?

A. y = -2.1 + 3
B. y = 2x + 3
C. y=-x+3
D. y = 3x +3 A B C D​

User Jvf
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1 Answer

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Final answer:

To find the equation of a line perpendicular to another line, we find the negative reciprocal of the slope of the given line and use the point-slope form of the equation. In this case, the equation of the line is y = x + 3.

Step-by-step explanation:

To find the equation of a line that is perpendicular to another line, we need to determine the negative reciprocal of the slope of the given line. The given line has the equation y = 21 - x, which can be rewritten as y = -x + 21. The slope of this line is -1. The negative reciprocal of -1 is 1, so the slope of the perpendicular line is 1.

Since the perpendicular line passes through the point (0,3), we can use the point-slope form of the equation: y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope. Substituting the values, we have y - 3 = 1(x - 0). Simplifying, we get y - 3 = x, or y = x + 3.

Therefore, the equation of the line that passes through the point (0,3) and is perpendicular to the line y = 21 - x is y = x + 3. So, the correct answer is C.

User Muhammad Amjad
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