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Which is (are) the root(s) of 49x²+49=98x?
a. x=-1
b. x=1
c x=+-1
d x=0

User Sidanmor
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1 Answer

6 votes

Final answer:

The roots of the equation 49x²+49=98x are x = -1 and x = 1.

Step-by-step explanation:

The given equation is 49x²+49=98x. To solve for the roots of this equation, we can rearrange it to the quadratic form ax²+bx+c=0, where a=49, b=-98, and c=-49. Now, we can use the quadratic formula x = (-b ± √(b^2 - 4ac)) / (2a) to find the roots. Plugging in the values, we get:

x = (-(-98) ± √((-98)^2 - 4(49)(-49))) / (2(49))

Simplifying further, we have:

x = (98 ± √(9604 + 9604)) / 98

x = (98 ± √(19208)) / 98

x = (98 ± 138.6) / 98

Therefore, the roots of the equation are x = -1 and x = 1. The answer is option a.

User Egidra
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