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The player pushes off of the back wall with a force of 100 N. If the mass of the player and

the ""stone"" together is equal to 110kg, at what rate will they accelerate down the lane?

1 Answer

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Final answer:

The force of friction between the losing player's feet and the grass is -108 N, while the force exerted by the winning player on the ground to move forward is 132 N. To find the force of friction, multiply the player's mass by their acceleration. To find the force exerted by the winning player, multiply their mass by their acceleration.

Step-by-step explanation:

The force of friction between the losing player's feet and the grass can be calculated using Newton's second law of motion. The player is accelerating backward at 1.20 m/s², so the net force acting on them is the force of friction, which can be found by multiplying the player's mass (90.0 kg) by their acceleration (-1.20 m/s²). Therefore, the force of friction is -108 N.

The force exerted by the winning player on the ground to move forward can also be calculated using Newton's second law. The player's mass plus equipment is 110 kg, and their acceleration is 1.20 m/s². The force exerted by the winning player is equal to their mass multiplied by their acceleration, which is 110 kg * 1.20 m/s² = 132 N.

A free-body diagram for this situation would show the forces acting on the losing player, including the force of friction and the force exerted by the opposing player. The net force equation would be Fnet = ma, where Fnet is the net force, m is the mass, and a is the acceleration.

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