Question

The height of a golf ball hit in the air is modeled by the equation H(t)=-16t²+48t, where H represents the height, in feet , and t represents the number of seconds that have passed since the ball was hit What is the height of the ball after 2 seconds?

The ball is at a height of _________ feet after 2 seconds.

Answer 1

To determine the height of the golf ball after 2 seconds, you need to substitute 't' with 2 in the equation H(t)=-16t²+48t, which results in a height of 32 feet.

Step-by-step explanation:

The height of a golf ball hit into the air is modeled by the equation H(t)=-16t²+48t, where H represents the height in feet and t represents the time in seconds since the ball was hit. To find the height of the ball after 2 seconds, we substitute t with 2 in the equation:

H(2)=-16(2)²+48(2)

First, we square 2: (2)²=4.

Then we multiply 16 by 4: -16 × 4 = -64.

Finally, we multiply 48 by 2 and add it to -64: 48 × 2 = 96 so H(2) = -64 + 96 = 32 feet.

Therefore, the golf ball is at a height of 32 feet after 2 seconds.