Question

A skater accelerating at 1.66 m/s2 travels 55.27 m after starting from rest. How long did the skater take to cover this much

ground?

Answer 1

The skater took approximately 8.17 seconds to cover 55.27 m at an acceleration of 1.66 m/s², which was determined by solving the kinematic equation for time.

Step-by-step explanation:

The student has asked a question related to the kinematics of a skater accelerating from rest, specifically seeking to determine how long it took to cover a distance of 55.27 m at an acceleration of 1.66 m/s2. Using the kinematic equation s = ut + (1/2)at2, where s is the distance, u is the initial velocity (0 since starting from rest), a is the acceleration, and t is the time, we can solve for the time 't' by rearranging the formula to t = √(2s/a).

By plugging in the given values:

• s = 55.27 m
• a = 1.66 m/s2

We get:

t = √(2 * 55.27 m / 1.66 m/s2)

t ≈ √(66.7062 s2)

t ≈ 8.169 s

Therefore, the skater took approximately 8.17 seconds to cover a distance of 55.27 m.