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The terminal point of O isV3 12:2What is sin ?O A. V3B.c.D.la S.

The terminal point of O isV3 12:2What is sin ?O A. V3B.c.D.la S.-example-1
User Rinna
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1 Answer

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if we draw the terminal point and draw a line to it from the origin we obtain something like this

This can form a right triangle in which we must find the hypotenuse


\begin{gathered} a^2+b^2=c^2 \\ ((1)/(2))^2+(\frac{\sqrt[]{3}}{2})^2=c^2 \\ (1)/(4)+(3)/(4)=c^2 \\ (4)/(4)=c^2 \\ c=\sqrt[]{1} \\ c=1 \end{gathered}

the sin is defines as the opposite (y) divided by the hypotenuse, in this case since the hypotenuse is equal to 1, the sin is equal to:


(1)/(2)

The terminal point of O isV3 12:2What is sin ?O A. V3B.c.D.la S.-example-1
User Jabacchetta
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