In exercises 9-12 the points represented by the table lie on a line. find the slope of the line

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asked May 5, 2024 219k views

1 Answer

Ptitaw · Answer 1 · 2024-05-11T12:51:07+0000

The slopes are:

$- Exercise 9: $ (1)/(2) $\\- Exercise 10: 0\\- Exercise 11: -4/0$

To find the slope of a line, you can use the formula:

$\text{Slope} (m) = \frac{\text{Change in } y}{\text{Change in } x}$

For each set of points, calculate the change in $ y $ and the change in $ x $, then use these values to find the slope.

**Exercise 9:**

$\text{Change in } x &= 3 - (-9) = 12 \\\\\text{Change in } y &= 4 - (-2) = 6 \\\\\text{Slope} &= (6)/(12) = (1)/(2)$

**Exercise 10:**

$\text{Change in } x &= 8 - (-1) = 9 \\\text{Change in } y &= -6 - (-6) = 0 \\\text{Slope} &= (0)/(9) = 0$

**Exercise 11:**

$\text{Change in } x &= 0 - 0 = 0 \\\text{Change in } y &= -4 - 0 = -4 \\$

Slope = (-4)/(0)

In Exercise 11, the slope is undefined because the change in $ x $ is zero, which results in division by zero. This indicates a vertical line.

So, the slopes are:

$- Exercise 9: $ (1)/(2) $\\- Exercise 10: 0\\- Exercise 11: -4/0$