Question

What is the new temperature ( 0C) of a 1.50 kg steel camping dish if it was heated from 15.0 0C by 61.0 kJ of heat.

Answer 1

Given:

The mass of steel is m = 1.5 kg

The initial temperature of the steel dish is

`T_i=15^(\circ)C`

The heat supplied to the steel dish is Q = 61 kJ

The specific heat capacity of steel is c = 452 J/kg deg C

To find: The final temperature of the steel dish, T_f.

Step-by-step explanation:

The formula to calculate the final temperature of the steel dish is

`\begin{gathered} Q=mc(T_f-T_i) \\ T_f=(Q)/(mc)+T_i \end{gathered}`

Substituting the values, the final temperature of the steel dish will be

`\begin{gathered} T_f=\frac{61*10^3\text{ J}}{1.5kg*452(J)/(kg^(\circ)C)\text{ }}+15 \\ =104.97^(\circ)C \end{gathered}`

Final Answer: The new temperature of the steel dish is 104.97 degrees Celsius.