Question

Bill Clinton spoke at the World Congress Center Campaigning for Hillary Clintonto be president on 9.26.16. Protestors for a reduction in the Prison Industrial Complex andWomen against abuse in the workplace organized against the speech. Bill thought the crowdwould be very large he estimated 1 person / 2.5 sq. feet. If the world Congress Venue is 220yards by 95 yards how many people did Bill Clinton's math team estimate would be at thespeech?

A. 75,240
B. 188100
C. 2.4 Million
D. 18810​

Answer 1

The estimated number of people expected by Bill Clinton's math team to attend the speech at the World Congress Venue is 75,240, arrived at by converting the venue's dimensions to feet, calculating the area, and then dividing by the density of 1 person per 2.5 sq. feet.

Step-by-step explanation:

To calculate the estimated number of people that Bill Clinton's math team thought would be at the speech, we need to determine the area of the World Congress Venue and then apply Bill's estimate of 1 person per 2.5 square feet.

First, we convert the dimensions of the venue from yards to feet since our density estimate is in square feet: 220 yards * 3 = 660 feet, 95 yards * 3 = 285 feet.

Next, we calculate the area: 660 feet * 285 feet = 188,100 square feet.

To find the estimated number of people, we divide the area by the density estimate provided, which results in: 188,100 square feet / 2.5 square feet per person = 75,240 people.

Therefore, the estimated number of people Bill Clinton's math team expected to be at the speech is 75,240, which corresponds to option A.