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A solid gold cube has a mass of 42.5 grams. It was dropped into a 10-mL graduated

cylinder containing 8.50 mL of water. The level of the water rises to 10.70 mL. What
is the density of gold?

User Jeovanny
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1 Answer

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The density of the gold cube is calculated using the mass of the cube (42.5g) and the volume of water displaced (2.20mL), resulting in a density of 19.32 g/mL.

The density of a solid gold cube can be determined using the mass of the gold and the volume of water displaced when the cube is submerged. The mass of the cube is given as 42.5 grams, and the volume of water displaced is the change in water level in the graduated cylinder, which is the final water level minus the initial water level (10.70 mL - 8.50 mL = 2.20 mL). Therefore, the volume of the gold cube is 2.20 mL. To calculate the density (d) of gold, use the formula d = mass/volume. The density of the gold cube is 42.5 grams / 2.20 mL = 19.32 g/mL.

User Hari Das
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