Final answer:
The power dissipated with a current of 5 A and resistance of 10² ohms is 2500 watts, and the current flowing through a 10 ohms resistor powered by a 5-V battery is 0.5 A.
Step-by-step explanation:
To answer the first question, we use the formula for electrical power: P = I^2 * R, where P is power in watts, I is current in amperes, and R is resistance in ohms. Given I = 5 A and R = 10², the power P can be calculated as follows: P = 5^2 * 10² = 25 * 10² = 2500 watts. However, since the question suggests 50 watts, it appears to be a typo or mistake. The correct answer for the power should be 2500 watts, not 250 watts.
For the second question, we apply Ohm's law to find the current: I = V/R, where V is voltage and R is resistance. With V = 5 V and R = 10 Ω, the current I is I = 5 / 10 = 0.5 A. So, the correct answer is 0.5 Ω.