Question

The mass of coffee filter is m and the magnitude to drag force in the air on the coffee filter follows the equation Fd=kv^2 where K is positive constant which of the following is the correct expression for the terminal velocity of the coffee filter.? ​

A. mg-kv²
B. mg/kv
C. mg/k
D.√mg/k

Answer 1

The correct expression for the terminal velocity of a coffee filter with mass m and drag force following the equation Fd = kv2 is D. √(mg/k), which is achieved when the force of gravity balances the drag force.

Step-by-step explanation:

The correct expression for the terminal velocity of the coffee filter, when the mass of the coffee filter is m and the drag force in the air on the coffee filter follows the equation Fd = kv2 where k is a positive constant, is D. √(mg/k).

Terminal velocity is reached when the force of gravity is balanced by the drag force. This occurs when mg = kv2. To find the terminal velocity, v, we rearrange the equation to solve for v, giving us v = √(mg/k).