Final answer:
To find the temperature increase of a 75 g sample of water that absorbs 925 J of heat with a specific heat of 4.186 J/g °C, use the formula ΔT = q / (mc). The calculated temperature increase is approximately 2.95 °C.
Step-by-step explanation:
The question asks how much the temperature of a 75 g sample of water will increase if it absorbs 925 J of heat, given that the specific heat of water is 4.186 J/g °C. We use the formula q = mcΔT, where q is the heat added (in joules), m is the mass of the water (in grams), c is the specific heat capacity, and ΔT is the change in temperature (in degrees Celsius). Rearranging the formula to solve for ΔT, we get ΔT = q / (mc). Plugging in the given values, we find the temperature increase:
ΔT = 925 J / (75 g × 4.186 J/g °C) = 925 J / 313.95 J/°C ≈ 2.95 °C
Thus, the water's temperature will increase by approximately 2.95 °C.