Final answer:
To find the mass of Ca equivalent to 77.4 grams of Zn, we calculate the number of moles of Zn and then find the equivalent mass of Ca by multiplying the moles by Ca's molar mass, resulting in 47.45 grams of Ca.
Step-by-step explanation:
To answer the question of how many grams of calcium (Ca) are in a sample that contains the same number of moles as a 77.4 gram sample of zinc (Zn), we first need to calculate the number of moles of Zn using its molar mass. The molar mass of zinc is 65.4 g/mol, meaning one mole of zinc weighs 65.4 grams. Thus, 77.4 grams of zinc is equivalent to 77.4 g ÷ 65.4 g/mol = 1.183 moles of Zn.
Since we want the same number of moles of Ca, and the molar mass of calcium is approximately 40.08 g/mol, we multiply the number of moles by the molar mass of calcium to find the equivalent mass in grams: 1.183 moles × 40.08 g/mol = 47.45 grams of Ca.