Question

3.00 m3 of a fixed mass of a gas at 150 kPa. Calculate the pressure if the volume is reduced to 1.20 m3 at a constant temperature.

Answer 1

P₂ = 375 kPa.

Step-by-step explanation:

Given that,

Initial volume, V₁ = 3 m³

Initial pressure, P₁ = 150 kPa

Final volume, V₂ = 1.2 m³

We need to find the final pressure.

At constant temperature,

`P\propto (1)/(V)\\\\P_1V_1=P_2V_2\\\\P_2=(P_1V_1)/(V_2)\\\\P_2=(150\ kPa* 3\ m^3)/(1.2\ m^3)\\\\P_2=375\ kPa`

So, the new pressure is 375 kPa.