Final answer:
To find out how much money Bobby needs to deposit in a bank account with 10% interest compounded annually to have $10,000 in ten years, the compound interest formula is used and adjusted to solve for the principal amount, yielding approximately $3,855.43.
Step-by-step explanation:
The question requires solving for the present value of a sum of money that grows with compound interest. First, we need to understand the formula for compound interest:
A = P(1 + r/n)^(nt), where:
- A is the amount of money accumulated after n years, including interest.
- P is the principal amount (the initial sum of money).
- r is the annual interest rate (decimal).
- n is the number of times that interest is compounded per year.
- t is the time the money is invested for in years.
Step-by-Step:
- Isolate the principal amount (P) in the compound interest formula:
P = A / (1 + r/n)^(nt). - For this question, A = $10,000, r = 10% or 0.10, n = 1 (compounded annually), and t = 10 years.
- Calculate the necessary initial deposit:
P = $10,000 / (1 + 0.10/1)^(1*10) = $10,000 / (1.10)^10. - Compute the calculation to find P.
- P ≈ $3,855.43, which is the amount Bobby needs to deposit into his bank account.