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To increase the difficulty of scoring, the students decided to cap off the bottom of one of the PVC pipes that are used as tubes that run from the holes on top to the bottom playing surface. The inside dimensions of the cylindrical tube are 2 in. diameter by 18 in. long. They filled 95% of the volume of the tube with water. How much water occupied that 95% volume?

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Final answer:

To determine the volume of water that occupies 95% of the tube's volume, we first calculated the total volume using the formula for the volume of a cylinder and then found 95% of that volume, resulting in approximately 53.407 cubic inches of water.

Step-by-step explanation:

The student's question involves finding out how much water occupied the 95% volume of the tube. The tube in question is a PVC pipe with an inside diameter of 2 inches and a length of 18 inches. To find the volume of cylindrical objects, the formula is V = πr²h, where r is the radius of the cylinder and h is its height.

First, we convert the diameter to radius by dividing it by 2, giving us a radius of 1 inch. Plugging the values into the formula gives us the total volume, and then we calculate 95% of that to find the volume of water that fills the tube.

Let's calculate the volume now:

  • Radius (r) = 2 inches / 2 = 1 inch
  • Height (h) = 18 inches
  • Total volume (V) = π * (1²) * 18
  • Total volume (V) = π * 1 * 18 = 18π cubic inches
  • Volume of water = 95% of total volume = 0.95 * 18π cubic inches

To get a numerical answer:

Volume of water = 0.95 * 18 * 3.14159 = approximately 53.407 cubic inches (since π is approximately 3.14159).

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