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Which is an equation of the line perpendicular to y=-22 + 1 and passes through

the point (3, 4)?

User Ctc
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1 Answer

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Final answer:

To find the equation of a line perpendicular to y = -173.51 + 4.83x that passes through the point (3, 4), calculate the negative reciprocal of the original line's slope and then use the point-slope formula with the given point.

Step-by-step explanation:

The original question has a typo. It should likely ask for the equation of a line perpendicular to y = mx + b, where m is the slope of the given line, and b is the y-intercept. However, 'y=-22 + 1' is not in the correct format of a linear equation. Nevertheless, as we discuss perpendicular lines, it is important to note that they have slopes that are negative reciprocals of each other. If the original line has a slope m, then the perpendicular line will have a slope of -1/m.

Looking at the references provided, if the line we want to be perpendicular to has a slope of 4.83, as indicated by the equation y = -173.51 + 4.83x (the line of best fit), the perpendicular line's slope would be -1/4.83. Once we have the slope, we can use the point it passes through, which is (3, 4), and the point-slope form of a line, y - y1 = m(x - x1), to find the specific equation of our line.

Step-by-Step Process:

  1. Find the slope of the given line (in this case, 4.83).
  2. Calculate the negative reciprocal to find the slope of the perpendicular line (-1/4.83).
  3. Use the point-slope formula with the given point (3, 4) and the perpendicular slope calculated in step 2.
  4. Simplify the equation to find the final answer.
User Esther H
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