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A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is 1 over 7 , and the probability of randomly pulling out a strawberry candy is 2 over 7 , what is the probability of randomly pulling out a pineapple candy?

A 3 over 7
B 4 over 7
C 5 over 7
D 6 over 7

User Strcat
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1 Answer

2 votes

The probability of randomly pulling out a pineapple candy is 4/7, considering the given probabilities for the other flavors, leading to answer option B.

The question asks for the probability of randomly pulling out a pineapple candy from a bowl that contains orange, strawberry, and pineapple flavored candies. Given that the probability of an orange candy is 1/7 and a strawberry candy is 2/7, we need to find the missing probability for the pineapple candy.

To find the probability of pulling out a pineapple candy, we need to subtract the probabilities of the other two flavors from the total probability, which is always 1. So:

Total probability = Probability of orange + Probability of strawberry + Probability of pineapple

1 = 1/7 + 2/7 + Probability of pineapple

Solving for the probability of pineapple:

Probability of pineapple = 1 - (1/7 + 2/7) = 1 - 3/7 = 4/7

Therefore, the answer is 4/7, which corresponds to option B.

User Sijmen Mulder
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