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A car traveling in a straight line has a velocity of 4.46 m/s at some instant. After 6.85 s its velocity is 8.82 m/s. What is the average acceleration in this time intervals? Answer in units of m/s²

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Final answer:

The average acceleration of the car is calculated using the change in velocity divided by the time interval, resulting in an average acceleration of 0.6365 m/s² over the 6.85 seconds.

Step-by-step explanation:

To calculate the average acceleration of a car over a given time interval, you can use the formula for acceleration which is the change in velocity (Δv) divided by the change in time (Δt). The formula is: a = Δv / Δt.

In this question, the initial velocity (vi) is 4.46 m/s and the final velocity (vf) after 6.85 seconds is 8.82 m/s. To find the change in velocity, subtract the initial velocity from the final velocity: Δv = vf - vi = 8.82 m/s - 4.46 m/s = 4.36 m/s. Now, divide this change in velocity by the time interval of 6.85 s to find the average acceleration.

The average acceleration is: a = Δv / Δt = 4.36 m/s / 6.85 s = 0.6365 m/s².

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