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What is the equation in standard form for a line that passes through the points (-3,2) and (-4,10)

User Ladie
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Final answer:

The equation in standard form for the line passing through the points (-3,2) and (-4,10) is 8x + y = -22.

Step-by-step explanation:

The equation in standard form for a line that passes through the points (-3,2) and (-4,10) can be found by first finding the slope of the line using the formula:

slope = (y2 - y1) / (x2 - x1)

Plugging in the values:

slope = (10 - 2) / (-4 - (-3))

Simplifying the equation gives a slope of -8. Using the point-slope form of the equation, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line, we can choose either point (-3,2) or (-4,10) to substitute in. Let's use (-3,2):

y - 2 = -8(x - (-3))

Simplifying the equation further gives:

y - 2 = -8x - 24

Rearranging the equation in standard form, we get:

8x + y = -22

User Sqe
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