Question

A car with an initial speed of 20 m/s accelerates at a uniform rate of 1.00 m/s2for 3.6 seconds. Find the speed and the displacement of the car during this time.

A. What is the car’s speed after 3.6 seconds:
B. Distance covered after 3.6 seconds

Answer 1

The car's speed after 3.6 seconds is 23.6 m/s and the distance covered is 78.48 m.

Step-by-step explanation:

To find the speed of the car after 3.6 seconds, we can use the formula: final velocity = initial velocity + (acceleration * time). Plugging in the given values, the initial velocity is 20 m/s, the acceleration is 1.00 m/s², and the time is 3.6 seconds. Therefore, the final velocity is 20 m/s + (1.00 m/s² * 3.6 s) = 20 m/s + 3.6 m/s = 23.6 m/s.

To find the displacement of the car during this time, we can use the formula: displacement = (initial velocity * time) + (0.5 * acceleration * time²). Plugging in the given values, the initial velocity is 20 m/s, the acceleration is 1.00 m/s², and the time is 3.6 seconds. Therefore, the displacement is (20 m/s * 3.6 s) + (0.5 * 1.00 m/s² * (3.6 s)²) = 72 m + 6.48 m = 78.48 m.