Final answer:
The centripetal acceleration of a car that completes a semicircular turn at a constant speed can be calculated using the formula. Let's say the radius of the turn is 15.0 meters and the time taken to complete the turn is 15.0 seconds. Given that the turn is a semicircular turn, which means the car completes half the circular path, we can use the formula to calculate the magnitude of the centripetal acceleration.
Step-by-step explanation:
The centripetal acceleration of a car that completes a semicircular turn at a constant speed can be calculated using the formula:
Centripetal acceleration = v^2 / r
where v is the velocity of the car and r is the radius of the turn. In this case, the speed of the car is constant and the radius of the turn is known. So, you can plug in the values and calculate the centripetal acceleration. The unit of centripetal acceleration is meters per second squared (m/s^2).
Let's say the radius of the turn is 15.0 meters and the time taken to complete the turn is 15.0 seconds. Given that the turn is a semicircular turn, which means the car completes half the circular path, we can use the formula:
Centripetal acceleration = (4πr) / (t^2)
This will give you the magnitude of the centripetal acceleration. Note: g in the question refers to the acceleration due to gravity, not grams. So, do not confuse g with grams in this context.