Answer:
It would cost $12 more for the company to trap 4 squirrels after the fee is raised.
Explanation:
To graph the equation C = 30 + 15s, we can create a simple line graph. The x-axis represents the number of squirrels (s), and the y-axis represents the total cost (C) in dollars.
We start by plotting the points using the given values:
Number of squirrels (s): 0, 1, 2, 3, 4, 5, 6
Total cost (C) in dollars: 30, 45, 60, 75, 90, 105, 120
Connecting these points with a straight line, we get a graph that starts at (0, 30) and increases by 15 units on the y-axis for every 1 unit increase on the x-axis.
b) For the equation C = 30 - 18s, the graph would be slightly different. Again, the x-axis represents the number of squirrels (s), and the y-axis represents the total cost (C) in dollars.
Plotting the points using the given values:
Number of squirrels (s): 0, 1, 2, 3, 4, 5, 6
Total cost (C) in dollars: 30, 12, -6, -24, -42, -60, -78
Connecting these points with a straight line, we get a graph that starts at (0, 30) and decreases by 18 units on the y-axis for every 1 unit increase on the x-axis.
c) To find out how much more it costs for the company to trap 4 squirrels after the fee is raised, we can compare the cost with the original fee and the new fee.
Using the original fee of $15 to trap each squirrel, the total cost to trap 4 squirrels would be:
C = 30 + (15 * 4) = 30 + 60 = $90
Using the raised fee of $18 to trap each squirrel, the total cost to trap 4 squirrels would be:
C = 30 + (18 * 4) = 30 + 72 = $102