Question

Two containers are leaking water at different rates.

One container has 100 gallons in it and is leaking out 3
gallons per minute. The other container has 150
gallons and is leaking out 5 gallons per minute. How
many minutes will pass before they have the same
amount of fluid? How much fluid will be in each tank?

Answer 1

It will take 25 minutes for the two containers to have the same amount of fluid. The amount of fluid in each tank will be 25 gallons.

Step-by-step explanation:

To determine how many minutes will pass before the two containers have the same amount of fluid, we can set up a proportional relationship based on the leak rates. Let's represent the amount of fluid in the first container after t minutes as 100 - 3t, and the amount of fluid in the second container after t minutes as 150 - 5t. To find the time when they have the same amount of fluid, we can set up an equation:

100 - 3t = 150 - 5t

Simplifying the equation:

2t = 50

t = 25 minutes

Therefore, it will take 25 minutes for the two containers to have the same amount of fluid. To find the amount of fluid in each tank, we can substitute t = 25 into the equations for the amount of fluid in each container:

Amount of fluid in the first container = 100 - 3(25) = 100 - 75 = 25 gallons

Amount of fluid in the second container = 150 - 5(25) = 150 - 125 = 25 gallons