Question

In an experiment to find the thermal energy transfer of a material the following characteristics were found:

Mass = 10 kg
Initial Temp = 20 C
Final Temp = 40 C
C = 1400 J/KgK
Calculate the thermal energy transfer for this experiment.

Answer 1

The thermal energy transfer for this experiment is 280,000 J.

Step-by-step explanation:

The thermal energy transfer for this experiment can be calculated using the formula:

Q = mcΔT

where Q is the thermal energy transfer, m is the mass of the material, c is the specific heat capacity of the material, and ΔT is the change in temperature.

Substituting the given values:

Mass (m) = 10 kg

ΔT = Final Temp - Initial Temp = 40°C - 20°C = 20°C

Specific heat capacity (c) = 1400 J/kgK

Plugging in these values into the formula, we get:

Q = 10 kg * 1400 J/kgK * 20°C = 280,000 J

Therefore, the thermal energy transfer for this experiment is 280,000 J.